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 how to use setDataSymbol |
| Posted by Ryan on Jan-14-2012 01:42 |
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I see in your samples that you always tend to use setDataSymbol at the same time you are passing in the dataset as in
Call layer1.addDataSet(data1, &H00ff00, "Atom Synthesizer").setDataSymbol( _
cd.GlassSphere2Shape, 11)
but I have the following:
Set layer1 = c.addLineLayer(dataY1, &H00ff00, ReportTitle)
and using setDataSymbol does not work with this, as in:
Set layer1 = c.addLineLayer(dataY1, &H00ff00, ReportTitle).setDataSymbol(cd.GlassSphereShape, 2, -1, -1, 1)
so I tried:
Call layer1.setDataSymbol(cd.GlassSphereShape, 2, -1, -1, 1)
the ASP error I get is:
Object doesn't support this property or method: 'layer1.setDataSymbol'
and this does not work either. So how to you set the DataSymbol separately from setting the DataSet/Array?
Thanks
-=Ryan |
| Re: how to use setDataSymbol |
| Posted by Peter Kwan on Jan-14-2012 04:18 |
|
Hi Ryan,
You can use:
Call layer1.getDataSet(0).).setDataSymbol(cd.GlassSphereShape, 11)
Hope this can help.
Regards
Peter Kwan |
| Re: how to use setDataSymbol |
| Posted by Ryan on Jan-14-2012 05:46 |
|
Yes, that helps. Thanks.
However, when I pass my array variable dataY1 to addLineLayer(dataY1, color, title)
I am getting a Error converting argument 1 to type class DoubleArray
However if I do the following:
response.write isArray(dataY1) & " "
response.write UBound(dataY1) & " "
response.write dataY1(0)
it writes:
True 1 23
so vbscript considers dataY1 an Array with one element, but ChartDirector seems to think it is not an array. So can CD not handle arrays with only one element?
Thanks
-=Ryan |
| Re: how to use setDataSymbol |
| Posted by Peter Kwan on Jan-15-2012 23:38 |
|
Hi Ryan,
According to your information, I believe vbscript considers dataY1 to be an Array with two elements, not one element. It is because UBound(dataY1) = 1, it means the array has two elements (with index 0 and 1). If you have never used the second element, it is uninitialized and vbscript may not consider it as a number. Consequently, dataY1 is not an array of numbers (only the first element is a number, but the second element is not a number).
To solve the problem, if dataY1 contains only 1 element, please declare it with the upper bound index of 0, like:
Dim dataY1(0)
Hope this can help.
Regards
Peter Kwan |
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